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once some people here have learned to take the limits of x approaches to infinite for various functions, they will understand better...
for now, look up on L'Hopital's rule also i forgot what is the question which this thread started upon lol |
it was does .99 = 1.. just by looking at the question should give the answer. :/ This thread is just a bunch of overanalysis.
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22/7 is approximated fraction, 1/3 is not
if you ever go and calculate it by hand or calculator you'd find that 22/7 is in no way cloase to 3.14159265359.......
though 1/3 is very accurately 0.3 repeating. I agree that 0.9 repeating is not so true for real life because you will never use that many numbers, but since we are talking about algebra here, I'd have to say 0.9 repeating=1 is algebratically true! :) |
Sigh. .9~ does equal one.
If you don't believe this last proof, then you have
1. Have disproven the value of the natural Logarithm "e" http://www.jimloy.com/algebra/series.htm 2. Have disproven the value of PI, as defined by the infinite sum of a geometric sequence http://www.jimloy.com/algebra/seriez.htm http://www.richland.cc.il.us/james/l...geometric.html As you can see, the infinite sum of a geometric sequence is equal to: S= a1 / (1-r ) It's proof is shown here: http://www.math.unl.edu/~gnorgard/calcres/gseries.html (just click "answer") That such a thing exists. Where S is the series. (an infinite sum of a geometric sequence) Thus, we fill in the values. .99999~ is a series, moddled by .9+.09+.009+.0009 ... (9*10^-n) a1 == .9 (the first value of the sequence) r == .1 (a(k+1)/a(k) where k is a positive integer) S = .9/(1-.1) == .9/.9 == 1 Thus, .9~ (the infinite geometric series, .9+.09+.009+.0009 ... (9*10^-n)) is equivalent to one. Remember, both PI and E are defined by an infinite series/infinite geometric sequence. Thus, you disagree with this, you disagree that PI == 3.141592 ... Again, for those who do not believe .3~ is equal to 1/3. The infinite sum of the sequence .3 + .03 + .003 ... (3*10^-n) is equal to al == .3 r == .1 .333~ = .3/(1-.1) == .3/.9 == 1/3 |
I'm in calculus, and I still don't believe it.. I don't think any formula or equation could convine me either... it's just one of those things...
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*shrugs and continues studying permutations*
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Jason425, if you have seen L'Hopital's Rule, (lim f(x)/g(x) = lim f'(x)/g'(x),)you will agree with me when I tell you that 1 (or any constant) divided by infiniti is equal to 0. 1 - .9~ = 1/(infiniti) Deny that! :evilking: |
No, I haven't seen it.. but we're just getting into limits.. so i'm sure soon i'll be corrupted into believing you two ;)
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